Matthias Gallé wrote:
bearophileh...@lycos.com wrote:
John O'Hagan:
li=['a', 'c', 'a', 'c', 'c', 'g', 'a', 'c']
for i in range(len(li)):
if li[i:i + 2] == ['a', 'c']:
li[i:i + 2] = ['6']
Oh well, I have done a mistake, it seems.
Another solution then:
'acaccgac'.replace("ac", chr(6))
'\x06\x06cg\x06'
Bye,
bearophile
Thanks bearophile and John for your quick answers.
Unfortunately, the int that can replace a sublist can be > 255, but
John's answer looks simple and good enough for me. I will use it as a
starting point.
John's solution changes the length of the list over which it's
iterating.
I'd suggest something more like:
li = ['a', 'c', 'a', 'c', 'c', 'g', 'a', 'c']
pos = 0
try:
while True:
pos = li.index('a', pos)
if li[pos : pos + 2] == ['a', 'c']:
li[pos : pos + 2] = [6]
pos += 1
except ValueError:
pass
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