On Thu, Sep 24, 2009 at 3:32 PM, Torsten Mohr <tm...@s.netic.de> wrote:
> a = [1, 2, 3, 4, 5, 6]
>
> for i, x in enumerate(a):
> if x == 3:
> a.pop(i)
> continue
>
> if x == 4:
> a.push(88)
>
> print "i", i, "x", x
>
> I'd like to iterate over a list and change that list while iterating.
> I'd still like to work on all items in that list, which is not happening
> in the example above.
>
I assume that by "a.push" you meant "a.append".
I believe this will do what you want:
a = [1, 2, 3, 4, 5, 6]
i = 0
while i < len(a):
x = a[i]
if x == 3:
a.pop(i)
i += 1
continue
if x == 4:
a.append(88)
print "i", i, "x", x
i += 1
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Daniel Stutzbach, Ph.D.
President, Stutzbach Enterprises, LLC <http://stutzbachenterprises.com>
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