On Wed, Sep 30, 2009 at 11:19 PM, Daniel Stutzbach <dan...@stutzbachenterprises.com> wrote: > On Thu, Sep 24, 2009 at 3:32 PM, Torsten Mohr <tm...@s.netic.de> wrote: >> >> a = [1, 2, 3, 4, 5, 6] >> >> for i, x in enumerate(a): >> if x == 3: >> a.pop(i) >> continue >> >> if x == 4: >> a.push(88) >> >> print "i", i, "x", x >> >> I'd like to iterate over a list and change that list while iterating. >> I'd still like to work on all items in that list, which is not happening >> in the example above. > > I assume that by "a.push" you meant "a.append". > > I believe this will do what you want: > > a = [1, 2, 3, 4, 5, 6] > i = 0 > while i < len(a): > x = a[i] > if x == 3: > a.pop(i) > i += 1 > continue > > if x == 4: > a.append(88) > > print "i", i, "x", x > i += 1 > > -- > Daniel Stutzbach, Ph.D. > President, Stutzbach Enterprises, LLC >
In the case of x == 3 when you remove an item from the list you should not increment the index. -- http://mail.python.org/mailman/listinfo/python-list
