All ran ok!!
Thanks a lot
Quoting MRAB <pyt...@mrabarnett.plus.com>:
Yasser Almeida Hernández wrote:
So, how can i pass an argument as a variable in this context...?
You can't pass arbitrary values on a command line. In this case, why not
just pass the path of the file?
s = 'command "%s" -i file2 -w 1.4 -o file3.out' % file1
Quoting MRAB <pyt...@mrabarnett.plus.com>:
Yasser Almeida Hernández wrote:
Hi all!!
I'm writing a script where i call a external program which
receive some arguments.
One of this arguments is stored in a variable, that is passed as
argument as well:
import os
...
f = open(file1, 'r')
s = 'command $f -i file2 -w 1.4 -o file3.out'
os.system(s)
...
When i run the script i get the next message...
'-i: No such file or directory'
... with a obvious error in the exit of the program. If i remove
the option -i i get the same error with every option, even with
those who don't get any file as argument. (file2 exist).
BUT, when i run the external program in a python shell, it works...
What's wrong?
The name 'f' in the Python script exists only in Python and is unrelated
to the '$f' that the shell sees.
--
http://mail.python.org/mailman/listinfo/python-list
--
Lic. Yasser Almeida Hernández
Center of Molecular Inmunology (CIM)
Nanobiology Group
P.O.Box 16040, Havana, Cuba
Phone: (537) 271-7933, ext. 221
----------------------------------------------------------------
Correo FENHI
--
http://mail.python.org/mailman/listinfo/python-list
