On Feb 22, 9:19 am, MRAB <pyt...@mrabarnett.plus.com> wrote: > Bryan wrote: > > I am looping through a list and creating a regular dictionary. From > > that dict, I create an ordered dict. I can't think of a way to build > > the ordered dict while going through the original loop. Is there a > > way I can avoid creating the first unordered dict just to get the > > ordered dict? Also, I am using pop(k) to retrieve the values from the > > unordered dict while building the ordered one because I figure that as > > the values are removed from the unordered dict, the lookups will > > become faster. Is there a better idiom that the code below to create > > an ordered dict from an unordered list? > > Why are you building a dict from a list and then an ordered dict from > that? Just build the ordered dict from the list, because it's behaves > like a dict, except for remembering the order in which the keys were > added.
Could you write some pseudo-code for that? I'm not sure how I would add the items to the OrderedDict while looping through the list. Wouldn't the list need to be sorted first (which in this case isn't practical)? -- http://mail.python.org/mailman/listinfo/python-list
