vincent wehren wrote: > "Volker Grabsch" <[EMAIL PROTECTED]> schrieb im > Newsbeitrag news:[EMAIL PROTECTED] > | However, I don't want to sort them the default way. These are birthdays, > | so only the month and day do matter, not the year. E.g.: > | ... > If you don't care about the year, why not just "normalize" the year > to all be the same using the replace method of the date instance? > Something like: > > d1 = datetime.date(2004, 12, 2) > d2 = datetime.date(2001, 12, 3) > d3 = datetime.date(2002, 12, 6) > d4 = datetime.date(1977, 12, 7) > dates =[d1,d2,d3,d4] > datesNorm = [obj.replace(year=1900) for obj in (dates)] > datesNorm.sort() > print datesNorm # etcetera
Or just use the .timetuple() method on datetime objects and sort on the 8th element of the 9-element tuple, which is the day-of-the-year. -Peter -- http://mail.python.org/mailman/listinfo/python-list
