On 7/29/2010 11:12 AM, wheres pythonmonks wrote:
Why is the default value of an int zero?
x = int
print x
<type 'int'>
x()
0
How do I build an "int1" type that has a default value of 1?
>>> class int1(object) :
... def __init__(self) :
... self.val = 1
... def __call__(self) :
... return(self.val)
...
>>> x = int1()
>>> x()
1
This isn't useful; you'd also have to define all the numeric operators
for this type. And then there are mixed-type conversion issues.
Inheriting from "int" is not too helpful, because you can't assign
to the value of the base class. "self=1" won't do what you want.
[Hopefully no speed penalty.]
In your dreams. Although all numbers in CPython are "boxed",
so there's more of a speed penalty with "int" itself than you
might expect. There are some C libraries for handling large
arrays if you really need to crunch numbers.
John Nagle
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