On 01/12/2010 01:08, Gnarlodious wrote:
This works for me:
def sendList():
return ["item0", "item1"]
def query():
l=sendList()
return ["Formatting only {0} into a string".format(l[0]), l[1]]
query()
However, is there a way to bypass the
l=sendList()
and change one list item in-place? Possibly a list comprehension
operating on a numbered item?
There's this:
return ["Formatting only {0} into a string".format(x) if i == 0
else x for i, x in enumerate(sendList())]
but that's too clever for its own good. Keep it simple. :-)
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