Gnarlodious wrote:
This works for me:def sendList(): return ["item0", "item1"] def query(): l=sendList() return ["Formatting only {0} into a string".format(l[0]), l[1]] query() However, is there a way to bypass the l=sendList() and change one list item in-place? Possibly a list comprehension operating on a numbered item? -- Gnarlie
what about def query():return ["Formating only {0} into a string".format(sendList()[0])] + sendList()[1:]
JM -- http://mail.python.org/mailman/listinfo/python-list
