Rickard Lindberg, 09.02.2011 09:32:
On Tue, Feb 8, 2011 at 5:41 PM, Chris Rebert<c...@rebertia.com> wrote:
Here is a bash script to reproduce my error:
Including the error message and traceback is still helpful, for future
reference.
Thanks for pointing it out.
#!/bin/sh
cat> å.timeline<<EOF
<snip>
EOF
python<<EOF
# encoding: utf-8
from xml.sax import parse
from xml.sax.handler import ContentHandler
parse(u"å.timeline", ContentHandler())
EOF
If I instead do
parse(u"å.timeline".encode("utf-8"), ContentHandler())
the script runs without errors.
Is this a bug or expected behavior?
Bug; open() figures out the filesystem encoding just fine.
Bug tracker to report the issue to: http://bugs.python.org/
Workaround:
parse(open(u"å.timeline", 'r'), ContentHandler())
When I tried your workaround, I still got this error:
Traceback (most recent call last):
File "<stdin>", line 4, in<module>
File "/usr/lib64/python2.7/site-packages/_xmlplus/sax/__init__.py",
line 31, in parse
parser.parse(filename_or_stream)
File "/usr/lib64/python2.7/site-packages/_xmlplus/sax/expatreader.py",
line 109, in parse
xmlreader.IncrementalParser.parse(self, source)
File "/usr/lib64/python2.7/site-packages/_xmlplus/sax/xmlreader.py",
line 119, in parse
self.prepareParser(source)
File "/usr/lib64/python2.7/site-packages/_xmlplus/sax/expatreader.py",
line 121, in prepareParser
self._parser.SetBase(source.getSystemId())
UnicodeEncodeError: 'ascii' codec can't encode character u'\xe5' in
position 0: ordinal not in range(128)
The open(..) part works fine, but there still seems to be a problem inside the
sax parser.
Did you read my reply?
Stefan
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