On 07/21/2011 08:46 AM, Web Dreamer wrote:
If you do not want to use 'float()' try:
int(x.split('.')[0])
This is right.
But, the problem is the same as with int(float(x)), the integer number is
still not as close as possible as the original float value.
I would in fact consider doing this:
int(round(float(x)))
This is wrong, since there is a loss of information in the float cast:
>>> float('9007199254740993.0')
9007199254740992.0
Notice the last digit switched from a 3 to a 2? Floats in python don't
have arbitrary accuracy. You would need to import decimal and use it
for rounding to work properly.
--
Bill
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