On 7/22/2011 1:55 AM, Frank Millman wrote:
As the OP, I will clarify what *my* requirement is. This discussion
has gone off at various tangents beyond what I was asking for.
Typical. Don't worry about it ;-).
As suggested above, I am only talking about a string containing int
literals followed by '.' followed by zero or more zeros.
int(float(x)) does the job,
Not given that specification.
>>> s='123456789012345678901.0'
>>> int(float(s))
123456789012345683968
and I am happy with that.
You should only be if you add 'with fewer than 18 digits' after 'int
literals' to your spec.
I was just asking if there were any alternatives.
>>> int(s.split('.')[0])
123456789012345678901
--
Terry Jan Reedy
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