[python 2.7] I have a (linux) pathname that I'd like to split completely into a list of components, e.g.: '/home/gyoung/hacks/pathhack/foo.py' --> ['home', 'gyoung', 'hacks', 'pathhack', 'foo.py']
os.path.split gives me a tuple of dirname,basename, but there's no os.path.split_all function. I expect I can do this with some simple loop, but I have such faith in the wonderfulness of list comprehensions, that it seems like there should be a way to use them for an elegant solution of my problem. I can't quite work it out. Any brilliant ideas? (or other elegant solutions to the problem?) -- George -- http://mail.python.org/mailman/listinfo/python-list
