On 28.07.2011 22:44, Ian Kelly wrote:
On Thu, Jul 28, 2011 at 2:18 PM, gry<georgeryo...@gmail.com> wrote:
[python 2.7] I have a (linux) pathname that I'd like to split
completely into a list of components, e.g.:
'/home/gyoung/hacks/pathhack/foo.py' --> ['home', 'gyoung',
'hacks', 'pathhack', 'foo.py']
os.path.split gives me a tuple of dirname,basename, but there's no
os.path.split_all function.
I expect I can do this with some simple loop, but I have such faith in
the wonderfulness of list comprehensions, that it seems like there
should be a way to use them for an elegant solution of my problem.
I can't quite work it out. Any brilliant ideas? (or other elegant
solutions to the problem?)
path = '/home/gyoung/hacks/pathhack/foo.py'
parts = [part for path, part in iter(lambda: os.path.split(path), ('/', ''))]
parts.reverse()
print parts
But that's horrendously ugly. Just write a generator with a while
loop or something.
pathname = '/home/gyoung/hacks/pathhack/foo.py'
parts = [part for part in pathname.split(os.path.sep) if part]
print parts
['home', 'gyoung', 'hacks', 'pathhack', 'foo.py']
--
http://mail.python.org/mailman/listinfo/python-list
