On Sun, Jul 22, 2012 at 11:56 AM, MRAB <pyt...@mrabarnett.plus.com> wrote: > Since the result is bound to the original name, the > result is the same.
Yes, assuming there are no other refs. >>> a=[3,2,1] >>> b=a >>> a=sorted(a) >>> a [1, 2, 3] >>> b [3, 2, 1] ChrisA -- http://mail.python.org/mailman/listinfo/python-list
