mooremath...@gmail.com wrote: > What's the best way to accomplish this? Am I over-complicating it? > My gut feeling is there is a better way than the following: > >>>> import itertools >>>> x = [1, 2, 3] >>>> y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in >>>> range(len(x)))) y > ['insertme', 1, 'insertme', 2, 'insertme', 3] > > I appreciate any and all feedback. >
Given the myriad of proposed solutions, I'm surprised nobody has suggested good old list slicing: >>> x = [1,2,3] >>> y = ['insertme']*(2*len(x)) >>> y[1::2] = x >>> y ['insertme', 1, 'insertme', 2, 'insertme', 3] -- Duncan Booth -- http://mail.python.org/mailman/listinfo/python-list