Duncan Booth wrote: > mooremath...@gmail.com wrote: > >> What's the best way to accomplish this? Am I over-complicating it? >> My gut feeling is there is a better way than the following: >> >>>>> import itertools >>>>> x = [1, 2, 3] >>>>> y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in >>>>> range(len(x)))) y >> ['insertme', 1, 'insertme', 2, 'insertme', 3] >> >> I appreciate any and all feedback. >> > > Given the myriad of proposed solutions, I'm surprised nobody has suggested > good old list slicing:
My post on gmane http://thread.gmane.org/gmane.comp.python.general/718940/focus=718947 apparently didn't make it through to the list. >>>> x = [1,2,3] >>>> y = ['insertme']*(2*len(x)) >>>> y[1::2] = x >>>> y > ['insertme', 1, 'insertme', 2, 'insertme', 3] An advantage of this approach -- it is usually much faster. -- http://mail.python.org/mailman/listinfo/python-list