On 12/24/12 09:36, Roy Smith wrote: > I have an integer that I want to encode as a hex string, but I don't > want "0x" at the beginning, nor do I want "L" at the end if it happened > to be a long. The result needs to be something I can pass to int(h, 16) > to get back my original integer. > > The brute force way works: > > h = hex(i) > assert h.startswith('0x') > h = h[2:] > if h.endswith('L'): > h = h[:-1] > > but I'm wondering if there's some built-in call which gives me what I > want directly. Python 2.7.
Would something like h = "%08x" % i or h = "%x" % i work for you? -tkc -- http://mail.python.org/mailman/listinfo/python-list