In article <mailman.1256.1356364625.29569.python-l...@python.org>, Tim Chase <python.l...@tim.thechases.com> wrote:
> On 12/24/12 09:36, Roy Smith wrote: > > I have an integer that I want to encode as a hex string, but I don't > > want "0x" at the beginning, nor do I want "L" at the end if it happened > > to be a long. The result needs to be something I can pass to int(h, 16) > > to get back my original integer. > > > > The brute force way works: > > > > h = hex(i) > > assert h.startswith('0x') > > h = h[2:] > > if h.endswith('L'): > > h = h[:-1] > > > > but I'm wondering if there's some built-in call which gives me what I > > want directly. Python 2.7. > > Would something like > > h = "%08x" % i > > or > > h = "%x" % i > > work for you? Duh. Of course. Thanks. -- http://mail.python.org/mailman/listinfo/python-list