On 01/27/2013 03:24 PM, Κώστας Παπαδόπουλος wrote:
Τη Κυριακή, 27 Ιανουαρίου 2013 9:12:16 μ.μ. UTC+2, ο χρήστης ru...@yahoo.com
έγραψε:
>> <python code>
>
> Yes indeed, there is no need to use a loop since i know the exact
number of items i'am expecting. Thanks you very much for clarifying this
to me:
> One last thing i want to ask you:
>
> ========================================
> try:
> cur.execute( '''SELECT host, userOS, browser, hits, lastvisit FROM
visitors
> WHERE counterID = (SELECT ID FROM counters WHERE URL = %s) ORDER BY
lastvisit DESC''', (htmlpage,) )
> except MySQLdb.Error, e:
> print ( "Query Error: ", sys.exc_info()[1].excepinfo()[2] )
> else:
> data = cur.fetchall()
>
> for host, useros, browser, hits, lastvisit in data:
> print ( "<tr>" )
>
> for item in host, useros, browser, hits, lastvisit.strftime('%A %e
%b, %H:%M').decode('cp1253').encode('utf8'):
> print ( "<td><center><b><font color=white> %s </td>" % item )
>
> sys.exit(0)
> =======================================
>
> That would be also written as:
>
> for row in data:
> print ("tr>")
> for item in row:
> print( "blah blah blah" )
>
> And that would make the code easier to read and more clear, but its
that 'lastvisit' column's value than needs formating,hence it makes me
use the above syntax.
>
> Is there any simpler way to write the above working code without the
need to specify all of the columns' names into the loop?
You can write:
for row in data:
print ("tr>")
row = list(row)
row[-1] = row[-1].strftime(...)
for item in row:
print( "blah blah blah" )
- mitya
--
Lark's Tongue Guide to Python: http://lightbird.net/larks/
The existence of any evil anywhere at any time absolutely ruins a total
optimism. George Santayana
--
http://mail.python.org/mailman/listinfo/python-list
