Τη Κυριακή, 27 Ιανουαρίου 2013 6:12:59 μ.μ. UTC+2, ο χρήστης ru...@yahoo.com έγραψε: > On 01/27/2013 02:04 AM, Ferrous Cranus wrote: > > >[...] > > > data = cur.fetchall() > > > for row in data: > > > print ( "<tr>" ) > > > > > > for item in row: > > > print( '''<td> <a > > href='http://www.%s?show=log'>%s</a> </td>''' % (item, item) ) > > >[...] > > > Okey, so far BUT i want the url linking to happen only for the URL column's > > > value, and not for the hits column too. How do i apply the url link to the > > > URL column's value only? > > > > Ferrous, > > > > 'row' has two items (the url and the hit count) in it, right? > > So print each separately rather than in a loop: > > > > data = cur.fetchall() > > for row in data: > > url = row[0] > > hits = row[1] > > print ( "<tr>" ) > > print( "<td> <a href='http://www.%s?show=log'>%s</a> </td>: % (url, > hits) )
Yes that can work, but i want to ask you if its possible to do the same thing from within the loop as i have it coded it until now. Is there a way to seperate the values within the loop? -- http://mail.python.org/mailman/listinfo/python-list
