On 2013-02-06 21:41, rh wrote:
I am curious to know if others would have done this differently. And if so
how so?
This converts a url to a more easily managed filename, stripping the
http protocol off.
This:
http://alongnameofasite1234567.com/q?sports=run&a=1&b=1
becomes this:
alongnameofasite1234567_com_q_sports_run_a_1_b_1
def u2f(u):
nx = re.compile(r'https?://(.+)$')
u = nx.search(u).group(1)
ux = re.compile(r'([-:./?&=]+)')
return ux.sub('_', u)
One alternate is to not do the compile step. There must also be a way to
do it all at once. i.e. remove the protocol and replace the chars.
Here's one way:
def u2f(u):
return re.sub(r'^https?://|([-:./?&=]+)', lambda m: '_' if
m.group(1) else '', u)
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