In article <8445e47e-7efe-4f37-9b40-db2896d58...@googlegroups.com>, Bhanu Karthik <bhanukarthik2...@gmail.com> wrote:
> data = sock.recv(RECV_BUFFER) > username = str(sock.getpeername()) > username = usernames[username] > if data == "/quit": > print data > sock.send("bye") > sock.close() > CONNECTION_LIST.remove(sock) > > > this is exact code.. > it is not even entering the if ... > I tried ( c= (data is '/quit')if c) That can't be the exact code. What you posted is a syntax error because the line after the "if" statement isn't indented properly. -- https://mail.python.org/mailman/listinfo/python-list