On Saturday, 23 November 2013 14:37:09 UTC-8, Roy Smith wrote: > In article <8445e47e-7efe-4f37-9b40-db2896d58...@googlegroups.com>, > > Bhanu Karthik <bhanukarthik2...@gmail.com> wrote: > > > > > data = sock.recv(RECV_BUFFER) > > > username = str(sock.getpeername()) > > > username = usernames[username] > > > if data == "/quit": > > > print data > > > sock.send("bye") > > > sock.close() > > > CONNECTION_LIST.remove(sock) > > > > > > > > > this is exact code.. > > > it is not even entering the if ... > > > I tried ( c= (data is '/quit')if c) > > > > That can't be the exact code. What you posted is a syntax error because > > the line after the "if" statement isn't indented properly.
indentation is correct when I trying to paste it here,it is showing like it is unindented. -- https://mail.python.org/mailman/listinfo/python-list