On 8/6/2014 6:44 PM, Tim Chase wrote:
On 2014-08-07 08:26, Ben Finney wrote:
Virgil Stokes <v...@it.uu.se> writes:
Suppose I have a directory C:/Test that is either empty or
contains more than 2000000 files, all with the same extension
(e.g. *.txt). How can I determine if the directory is empty
WITHOUT the generation of a list of the file names in it (e.g.
using os.listdir('C:/Test')) when it is not empty?
Certainly ‘os.listdir(foo)’ is the simplest way to determine the
entries in a directory, and thereby to test whether it is empty.
That simplicity is very valuable, and you should have a compelling,
*measured* reason to do something more complicated. What is it?
With all the changes in 2->3 where many listy things were made into
iteratory things (e.g. range()), I was surprised that os.listdir()
didn't do likewise since I believe that just about every OS uses some
iterator-like call behind the scenes anyways.
I expect 3.5 will have a scandir generator function.
The difference in timings when serving a web-request are noticeable
(in my use-case, I had to change my algorithm and storage structure
to simplify/avoid heavily-populated directories)
-tkc
--
Terry Jan Reedy
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