Virgil Stokes <[email protected]> writes:
> Suppose I have a directory C:/Test that is either empty or contains
> more than 2000000 files, all with the same extension (e.g. *.txt). How
> can I determine if the directory is empty WITHOUT the generation of a
> list of the file names in it (e.g. using os.listdir('C:/Test')) when
> it is not empty?
def is_empty_dir(dirpath):
return next(scandir(dirpath), None) is None
https://github.com/benhoyt/scandir
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Akira
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