On Fri, Oct 24, 2014 at 10:37 AM, Seymore4Head <Seymore4Head@hotmail.invalid> wrote: > If I could explain to you why something doesn't work then I could fix > it myself. I don't understand why it doesn't work. The best I can do > is repost the code.
You don't need to be able to explain why it doesn't work. You just need to be able to explain what you expected it to do and what it actually did. Posting the code and the traceback that you get is a fine start. > if y in lst(range(1,10)): The name of the builtin is "list". It's a function* that takes an argument and uses it to construct a list, which it returns. "lst" is the name of some specific list that you're using in your code. It's not a function, which is why the error is complaining that it isn't callable. *Actually it's a type object, and calling it causes an instance of the type to be constructed, but for all intents and purposes here it works exactly like a function. -- https://mail.python.org/mailman/listinfo/python-list