On Fri, 24 Oct 2014 11:52:15 -0600, Ian Kelly <ian.g.ke...@gmail.com> wrote:
>On Fri, Oct 24, 2014 at 11:03 AM, Seymore4Head ><Seymore4Head@hotmail.invalid> wrote: >> Actually I was a little frustrated when I added that line back in as >> the other lines all work. >> Using list(range(10)) Doesn't throw an error but it doesn't work. >> >> http://i.imgur.com/DTc5zoL.jpg >> >> The interpreter. I don't know how to use that either. > >Try both of these in the interpreter, and observe the difference: > >7 in range(10) > >"7" in range(10) > >Do you understand what the difference between 7 and "7" is? I do understand that. 7 is a number and "7" is a string. What my question was...and still is...is why Python 3 fails when I try using y=1 800 get charter y in range str(range(10)) should work because y is a string and str(range(10)) should be "y" in str(1) fails. It doesn't give an error it's just not True when y is a number. These hints are just not working. I am too thick for hints. :) If you could use it in the code, I might understand. The other work arounds that were posted work. I have used them. str(range(10)) doesn't work. import string def nametonumber(name): lst=[] nx=[] digit=[] digit="".join(str(i) for i in range(10)) for x in name: lst.append(x) for y in (lst): if y in list(range(1,10)): #if y in "1234567890": #if y.isdigit(): #if y in digit: #if y in string.digits: nx.append(y) if y in " -()": nx.append(y) if y in "abc": nx.append("2") if y in "def": nx.append("3") if y in "ghi": nx.append("4") if y in "jkl": nx.append("5") if y in "mno": nx.append("6") if y in "pqrs": nx.append("7") if y in "tuv": nx.append("8") if y in "wxyz": nx.append("9") number="".join(e for e in nx) return number a="1-800-getcharter" print (nametonumber(a))#1800 438 2427 837 a="1-800-leo laporte" print (nametonumber(a)) a="1 800 dialaho" print (nametonumber(a)) Please -- https://mail.python.org/mailman/listinfo/python-list