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On 11/04/2014 08:52 AM, Roberto Martínez wrote:
I am trying to replace dinamically the __call__ method of an object using
setattr.
Example:
$ cat testcall.py
class A:
def __init__(self):
setattr(self, '__call__', self.newcall)
def __call__(self):
print("OLD")
def newcall(self):
print("NEW")
a=A()
a()
I expect to get "NEW" instead of "OLD", but in Python 3.4 I get "OLD".
$ python2.7 testcall.py
NEW
$ python3.4 testcall.py
OLD
I have a few questions:
- Is this an expected behavior?
- Is possible to replace __call__ dinamically in Python 3? How?
In 2.7 that would be a classic class, about which I know little.
In 3.x you have a new class, one which inherits from 'object'. When you replace __call__ you need to replace it the
class, not on the instance:
setattr(__self__.__class__, self.newcall)
--
~Ethan~
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