On 28/03/2015 09:53, Steven D'Aprano wrote:
On Sat, 28 Mar 2015 10:08 am, BartC wrote:
An alternate syntax might be:
hello = .string()
That should have been .strip()
loop_node =. next
Why propose that?
Every other augmented assignment has the operator on the left hand side of
the equals. Greater-than, less-than, and not-equal all have the symbol on
the left hand side of the equals:
+= -= *= **= /= //= %= |= ^= &= <= >= != =.
> ... and I'm dubious about pretending that . is an operator
I see where you're coming from now. You're thinking that it is "." that
is the operator, but I'm looking at "strip()" as the operator that is
being applied.
I see the "." as just a bit of necessary syntax that introduces this
style of operator as a /unary/ operation, not a binary operation like
all those examples.
Maybe that's just the way Python does it. However, take this example
using negation:
a = -a
which is clearly applying a unary operator, and imagine there existed a
method (if that's the word) called "neg", that also returned the
negative value of its operand:
a = a.neg()
This does exactly the same thing. But suddenly you're now applying a
binary operator "." instead of a unary one!
(I'm not sure how this all applies to the loop_node.next example, but
even here I don't count the "." as an operator, but syntax. In the
languages I'm used to, the right-hand-side cannot be a conventional
operand.)
--
Bartc
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