On Fri, Dec 11, 2015 at 9:10 AM, ICT Ezy <ict...@gmail.com> wrote: > Dear All, > Very Sorry for the my mistake here. I code here with mu question ... > > My Question: > > A,B=C,D=10,11 > print(A,B,C,D) > #(10,11,10,11) --> This is OK! > > a=1; b=2 > a,b=b,a > print(a,b) > # (1,2) --> This is OK!
This actually results in (2, 1), which is expected; you assign 1 to a and 2 to b and then swap the values. > x,y=y,x=2,3 > print(x,y) > # (3,2) --> Question: How to explain it? > # Not understand this process. Pl explain ... The assignments happen from left to right. First, (2,3) is assigned to (x,y), which has the effect of assigning 2 to x and then 3 to y. Next, (2,3) is assigned to (y,x), whas the effect of assigning 2 to y and then 3 to x, overwriting the previous assignments. Then when you do the print, x has the value 3, and y has the value 2. -- https://mail.python.org/mailman/listinfo/python-list
