On Friday, December 11, 2015 at 8:24:45 AM UTC-8, Robin Koch wrote: > Am 11.12.2015 um 17:10 schrieb ICT Ezy: > > Dear All, > > Very Sorry for the my mistake here. I code here with mu question ... > > > > My Question: > > > > A,B=C,D=10,11 > > print(A,B,C,D) > > #(10,11,10,11) --> This is OK! > > > > a=1; b=2 > > a,b=b,a > > print(a,b) > > # (1,2) --> This is OK! > > > > x,y=y,x=2,3 > > print(x,y) > > # (3,2) --> Question: How to explain it? > > # Not understand this process. Pl explain ... > > What else would you expect? > > Assigning goes from right to left: > > x,y=y,x=2,3 > > <=> > > y, x = 2, 3 > x, y = y, x > > Otherwise the assignment x, y = y, x would not make any sense, since x > and y haven't any values yet. > > And the execution from right to left is also a good choice, because one > would like to do something like: > > x = y = z = 0 > > Again, assigning from left to right woud lead to errors. > > -- > Robin Koch
Thank you very much your answer, I had not known assignment id Right2Left before. I done it. -- https://mail.python.org/mailman/listinfo/python-list
