On 2016-02-29 13:45, jonas.thornv...@gmail.com wrote:
I have a problem programming uniform networks, "x nodes with y links" that turn out to be really hairy to solve for me and i feel i really lack the programming features"Actually i program in javascript" but the problem seem general for all programming languages including Pyhton. For a beautiful solution it would require "If in list/array return boolean" "If not in list/array return boolean". But there is no such feature Python nor Javascript, so instead i set boolean value "inlist" to false and loop thru, to see if it is already in list. If not it is added to list. So if the current node i generate links for is x and i try to generate a link to node z, and z's links exhausted i will add it to exhausted list. And if there is node-x exhausted entries in list, well then script should break because it will lock into a cycle. The cyclic lockup is due to only a subset of the networks on the form (links*deep)+1=nodes is possible. So what i need is to know howto write "if list/array ***empty*** do {something}" I sure know howto check if an array have 1 element 2,3,4 but how do you check for empty. I think it is crazy that you can not do general comparissons of the type If in list/array If not in list/array But it is even more crazy that you can not check if list/array is empty, that is just madness.
Does this help? >>> items = ['a', 'b', 'c', 'd', 'e'] >>> 'c' in items True >>> 'f' in items False >>> len(items) 5 >>> len([]) 0 -- https://mail.python.org/mailman/listinfo/python-list
