On Monday, 15 August 2016 00:03:59 UTC+5:30, MRAB wrote: > On 2016-08-14 19:17, Atri Mahapatra wrote: > > I have a list of dictionaries which look like this: > > [{'Width': 100, 'Length': 20.0, 'Object': 'Object1'}, {'Width': 12.0, > > 'Length': 40.0, 'Object': 'Object2'}...... so on till 10] > > > > I would like to find the first index in the list of dictionaries whose > > length is greater than a particular value > > > > f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii]['Length'] > > > m][0] and it throws an error > > > > can anyone suggest a way to do it? > > > What is the error?
Traceback (most recent call last): File "<pyshell#12>", line 1, in <module> f(lengthlist, 10) f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii] > m][0] TypeError: unorderable types: dict() > int() -- https://mail.python.org/mailman/listinfo/python-list