On 2016-08-14 19:40, Atri Mahapatra wrote:
On Monday, 15 August 2016 00:03:59 UTC+5:30, MRAB wrote:
On 2016-08-14 19:17, Atri Mahapatra wrote:
> I have a list of dictionaries which look like this:
> [{'Width': 100, 'Length': 20.0, 'Object': 'Object1'}, {'Width': 12.0,
'Length': 40.0, 'Object': 'Object2'}...... so on till 10]
>
> I would like to find the first index in the list of dictionaries whose length
is greater than a particular value
>
> f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii]['Length'] >
m][0] and it throws an error
>
> can anyone suggest a way to do it?
>
What is the error?
Traceback (most recent call last):
File "<pyshell#12>", line 1, in <module>
f(lengthlist, 10)
f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii] > m][0]
TypeError: unorderable types: dict() > int()
That's not the same code as your original post.
Your original post has:
seq[ii]['Length'] > m
which is correct, but your traceback shows:
seq[ii] > m
which tries to compare the entire dict to m, hence the exception.
--
https://mail.python.org/mailman/listinfo/python-list
