billiejoex wrote:
> Hi all. I'd need to aproximate a given float number into the next (int)
> bigger one. Because of my bad english I try to explain it with some example:
>
> 5.7 --> 6
> 52.987 --> 53
> 3.34 --> 4
> 2.1 --> 3
>
> Regards
>
>
math.ceil returns what you need but as a float, then create an int
>>> import math
>>> math.ceil (12.3)
13.0
>>> int (math.ceil (12.3))
13
hth
--
rafi
"Imagination is more important than knowledge."
(Albert Einstein)
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