Il 13/04/2021 01:11, Rich Shepard ha scritto:
I'm running Slackware64-14.2 and keep a list of installed packages. When a
package is upgraded I want to remove the earlier version, and I've not
before written a script like this. Could there be a module or tool that
already exists to do this? If not, which string function would be best
suited to the task?
Here's an example:
atftp-0.7.2-x86_64-2_SBo.tgz
atftp-0.7.4-x86_64-1_SBo.tgz
and there are others like this. I want the python3 script to remove the
first one. Tools like like 'find' or 'sort -u' won't work because while the
file name is the same the version or build numbers differ.
All suggestions welcome.
Rich
If I understand your problem correctly, the problem would be dealing
with numbers as such in file names. This is just a track but it might
help you. This example splits filenames into strings and numbers into
tuples, appends the tuple into a list, and then sorts the list:
files = ['atftp-0.7.4-x86_64-2_SBo.tgz', 'atftp-0.7.2-x86_64-1_SBo.tgz']
digit = None
da = ''
tfn = tuple()
ltafn = list()
for f in files:
for c in f:
if str(c).isdigit():
if not digit:
if len(da) > 0:
tfn += (da,)
da = ''
digit = True
da += c
else:
da += c
else:
if digit:
if len(da) > 0:
tfn += (int(da),)
da = ''
digit = False
da += c
else:
da += c
if len(da) > 0:
if da.isdigit():
tfn += (int(da),)
else:
tfn += (da,)
da = ''
ltafn += [tfn, ]
tfn = ()
ltafn.sort()
for t in files:
print(t)
print()
for t in ltafn:
nn = ''
for f in t:
nn += str(f)
print(nn)
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