Hi,
No, I’ve checked leading/trailing whitespace, it seems to be related to the
variables that are returned from eyed3 in this case, for instance, I added a
check for None:
myTitleName = myID3.tag.title
if myTitleName is None:
continue
Seems like it can return a null object (or none?).
> On 7 Jun 2022, at 22:35, De ongekruisigde
> <ongekruisi...@news.eternal-september.org> wrote:
>
> On 2022-06-07, Dave <d...@looktowindward.com
> <mailto:d...@looktowindward.com>> wrote:
>> Thanks a lot for this! isDigit was the method I was looking for and couldn’t
>> find.
>>
>> I have another problem related to this, the following code uses the code you
>> just sent. I am getting a files ID3 tags using eyed3, this part seems to
>> work and I get expected values in this case myTitleName (Track name) is set
>> to “Deadlock Holiday” and myCompareFileName is set to “01 Deadlock Holiday”
>> (File Name with the Track number prepended). The is digit test works and
>> myCompareFileName is set to “Deadlock Holiday”, so they should match,
>> right?
>>
>> However the if myCompareFileName != myTitleName always gives a mismatch!
>> What could cause two string that look the fail to not match properly?
>
> Possibly leading or trailing spaces, or upper/lower case differences?
>
>
>> myCompareFileName = myFile
>> if myCompareFileName[0].isdigit() and myCompareFileName[1].isdigit():
>> myCompareFileName = myCompareFileName[3:]
>>
>> if myCompareFileName != myTitleName:
>> print('File Name Mismatch - Artist: ',myArtistName,' Album:
>> ',myAlbumName,' Track:',myTitleName,' File: ',myFile)
>> Thanks a lot
>> Dave
>>
>>> On 7 Jun 2022, at 21:58, De ongekruisigde
>>> <ongekruisi...@news.eternal-september.org> wrote:
>>>
>>> On 2022-06-07, Dave <d...@looktowindward.com> wrote:
>>>> Hi,
>>>>
>>>> I’m new to Python and have a simple problem that I can’t seem to find the
>>>> answer.
>>>>
>>>> I want to test the first two characters of a string to check if the are
>>>> numeric (00 to 99) and if so remove the fist three chars from the string.
>>>>
>>>> Example: if “05 Trinket” I want “Trinket”, but “Trinket” I still want
>>>> “Trinket”. I can’t for the life of work out how to do it in Python?
>>>
>>>
>>> s[3:] if s[0:2].isdigit() else s
>>>
>>>
>>>> All the Best
>>>> Dave
>>>>
>>>
>>> --
>>> <StevenK> You're rewriting parts of Quake in *Python*?
>>> <knghtbrd> MUAHAHAHA
>>> --
>>> https://mail.python.org/mailman/listinfo/python-list
>>
>
>
> --
> <StevenK> You're rewriting parts of Quake in *Python*?
> <knghtbrd> MUAHAHAHA
> --
> https://mail.python.org/mailman/listinfo/python-list
> <https://mail.python.org/mailman/listinfo/python-list>
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