s0 = r'\x0a' At this moment it was done by def to1byte(matchobj): ....return chr(int('0x' + matchobj.group(1), 16)) s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)
But, is it that difficult on doing this simple thing? --Jach -- https://mail.python.org/mailman/listinfo/python-list