s0 = r'\x0a'
At this moment it was done by

    def to1byte(matchobj):
    ....return chr(int('0x' + matchobj.group(1), 16))
    s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)

But, is it that difficult on doing this simple thing?

--Jach
-- 
https://mail.python.org/mailman/listinfo/python-list

Reply via email to