On 07/12/2022 03:23, Jach Feng wrote:
s0 = r'\x0a'
At this moment it was done by

     def to1byte(matchobj):
     ....return chr(int('0x' + matchobj.group(1), 16))
     s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)

But, is it that difficult on doing this simple thing?

>>> import codecs
>>> codecs.decode(r"\x68\x65\x6c\x6c\x6f\x0a", "unicode-escape")
'hello\n'

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