On 28Feb2023 00:11, Jen Kris <jenk...@tutanota.com> wrote:
When matching a string against a longer string, where both strings have spaces
in them, we need to escape the spaces.
This works (no spaces):
import re
example = 'abcdefabcdefabcdefg'
find_string = "abc"
for match in re.finditer(find_string, example):
print(match.start(), match.end())
That gives me the start and end character positions, which is what I want.
However, this does not work:
import re
example = re.escape('X - cty_degrees + 1 + qq')
find_string = re.escape('cty_degrees + 1')
for match in re.finditer(find_string, example):
print(match.start(), match.end())
I’ve tried several other attempts based on my reseearch, but still no
match.
You need to print those strings out. You're escaping the _example_
string, which would make it:
X - cty_degrees \+ 1 \+ qq
because `+` is a special character in regexps and so `re.escape` escapes
it. But you don't want to mangle the string you're searching! After all,
the text above does not contain the string `cty_degrees + 1`.
My secondary question is: if you're escaping the thing you're searching
_for_, then you're effectively searching for a _fixed_ string, not a
pattern/regexp. So why on earth are you using regexps to do your
searching?
The `str` type has a `find(substring)` function. Just use that! It'll be
faster and the code simpler!
Cheers,
Cameron Simpson <c...@cskk.id.au>
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