The base class:
class Constraint(object): def __init__(self, strength): super(Constraint, self).__init__() self.strength = strength def satisfy(self, mark): global planner self.choose_method(mark) The subclass: class UrnaryConstraint(Constraint): def __init__(self, v, strength): super(UrnaryConstraint, self).__init__(strength) self.my_output = v self.satisfied = False self.add_constraint() def choose_method(self, mark): if self.my_output.mark != mark and \ Strength.stronger(self.strength, self.my_output.walk_strength): self.satisfied = True else: self.satisfied = False The base class Constraint doesn’t have a "choose_method" class method, but it’s called as self.choose_method(mark) on the final line of Constraint shown above. My question is: what makes "choose_method" a method of the base class, called as self.choose_method instead of UrnaryConstraint.choose_method? Is it super(UrnaryConstraint, self).__init__(strength) or just the fact that Constraint is its base class? Also, this program also has a class BinaryConstraint that is also a subclass of Constraint and it also has a choose_method class method that is similar but not identical: def choose_method(self, mark): if self.v1.mark == mark: if self.v2.mark != mark and Strength.stronger(self.strength, self.v2.walk_strength): self.direction = Direction.FORWARD else: self.direction = Direction.BACKWARD When called from Constraint, it uses the one at UrnaryConstraint. How does it know which one to use? Thanks, Jen -- https://mail.python.org/mailman/listinfo/python-list
