Neal Becker wrote: > I can do this with a generator: > > def integers(): > x = 1 > while (True): > yield x > x += 1 > > for i in integers(): > > Is there a more elegant/concise way? >
import itertools for i in itertools.count(): print i Will McGugan -- http://www.willmcgugan.com "".join({'*':'@','^':'.'}.get(c,0) or chr(97+(ord(c)-84)%26) for c in "jvyy*jvyyzpthtna^pbz") -- http://mail.python.org/mailman/listinfo/python-list