Claudio Grondi wrote: > As also the fact, that when > a = [1,2.0,3L] > b = [1.0,2,3 ] > a==b # gives True > even if the objects in the lists are actually different, > or when the objects being members of the list redefine __eq__ so, that > no matter how different they are, the lists always compare True. > Can't you use "a is b" in this case to test for what you want ?
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