"Math" <[EMAIL PROTECTED]> wrote:
>
>Thanks  this does the job
>And yes,  I really need this accuracy..

Then you need to understand that you don't really HAVE this accuracy.  You
are fooling yourself.  1090.516455488 cannot be represented exactly in
binary, just like 1/3 cannot be represented exactly in decimal.  Further,
the more arithmetic you do, the less precise is your result.

Floating point is a very tricky world of approximation.
-- 
- Tim Roberts, [EMAIL PROTECTED]
  Providenza & Boekelheide, Inc.
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