I know I can do it this way. I wanted to know if there was another way. Fredrik Lundh wrote: > "manstey" <[EMAIL PROTECTED]> wrote: > > > but I can't find an equivalent code for: > > > > a='xfsdfyysd asd x' > > tup=('x','yy','asd') > > if tup in a: > > < ...> > > > > I can only do: > > > > if 'x' in a or 'yy' in a or 'asd' in a: > > <...> > > > > but then I can't make the if clause dependent on changing value of tup. > > > > Is there a way around this? > > is the "def" statement broken in your Python version ? > > def findany(text, words): > for w in words: > if w in text: > return True > return False > > if findany(a, tup): > ... > > </F>
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