May be your provider blocks it... try config your app to communicate through
4400 or any http port that should be allowed by your provider...hope it can
helps.
Ludo
From: João Abrantes
Sent: Monday, January 07, 2008 11:04 AM
To: Ludovic Reenaers ; python-win32@python.org
Subject: RE: [python-win32] Socket Connection Problem
To fix the nat or port forwarding problem i went to my router's page and
entered the following on the NAPT virtual server: "Transport Type: TCP ,
External Start Port: 1236, External End Port: 1236, Internal Start Port: 1236,
Internal End Port: 1236" since the socket server is binded to the port 1236
this should fix it right? But it still doesn't work.. lol I have tried to
change a lot of network configs and nothing worked ... any ideas pls?
------------------------------------------------------------------------------
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; python-win32@python.org
Subject: Re: [python-win32] Socket Connection Problem
Date: Mon, 7 Jan 2008 00:59:22 +0100
may be you are behind a router or proxy or whatever then your external ip is
actually the network device connected to the internet. this device may probably
be tuned for NAT or port forwarding... I 'm not sure this your issue but it
could be.
it is for sure a network config issue because the port is open (since you can
connect interenally.) and firewall is disabled.
good luck
From: João Abrantes
Sent: Sunday, January 06, 2008 9:49 PM
To: python-win32@python.org
Subject: [python-win32] Socket Connection Problem
Hello everyone.
I have made a socket server on one of my lan computer and I made a socket
client on other lan computer. When I try to access the server socket using the
computer External IP it gives me an error: (10061, 'Connection refused'). If I
use it's internal ip the connection is accepted... I think that I am not able
to connect to any computer outside my lan because the program only checks for
Internal IPs how can I change that?
P.S. I already disabled my firewall. The socket server is binded to:
s.bind(('0.0.0.0.',1236)).
Thanks and Regards
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