Sorry for the late thank you Justin!
On Tuesday, October 1, 2013 5:43:59 PM UTC+7, Justin Israel wrote:
>
> You can use a single regular expression, with capture groups:
>
> In [1]: import re
>
> In [2]: path = r'P:\foo\bar\biz\scene\ch01\seq001\s0090\anim\foo\bar\biz'
>
> In [3]: match = re.search(r'(ch\d{2})\\(seq\d{3})\\(s\d{4})', path)
>
> In [4]: if match:
> ...: print match.groups()
> ...:
> ('ch01', 'seq001', 's0090')
>
> In [5]: match.group(1)
> Out[5]: 'ch01'
>
> In [6]: match.group(2)
> Out[6]: 'seq001'
>
> In [7]: match.group(3)
> Out[7]: 's0090'
>
> In [8]: match = re.search(r'ch(\d{2})\\seq(\d{3})\\s(\d{4})', path)
>
> In [9]: print match.groups()
> ('01', '001', '0090')
>
>
> On Oct 1, 2013, at 11:06 PM, Panupat Chongstitwattana wrote:
>
> > Hi.
> >
> > I have this string
> >
> > path = r'P:\<various directories>\scene\ch01\seq001\s0090\anim\.......'
> >
> > I want to split out the ch01, seq001 and s0090 into 3 variables (or a
> list). Is there a way to do this with regex in a single line? Maybe with
> re.split(...)
> >
> > Currently I do it in 3 different steps
> >
> > find = re.findall(r'ch\d\d', path)
> > if find: ch = find[0]
> >
> > find = re.findall(r'seq\d\d', path)
> > if find: seq = find[0]
> >
> > etc.
> >
> > Thanks
> >
>
>
>
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