I had previously suggested a solution like this:
match = re.search(r'ch(\d{2})\\seq(\d{3})\\s(\d{4})', path)
match.groups()
# ('01', '001', '0090')
Do you think your version, using multiple OR'd patterns might produce a lot
of unwanted and non-specifically ordered matches?
aPath = r'P:\<various
directories>\scene\ch01\seq001\s0090\anim\search02_foo\apples1000.......'
re.findall(r'(?:ch\d{2})|(?:seq\d{2})|(?:s\d{4})', aPath)
# ['ch01', 'seq00', 's0090', 'ch02', 's1000']
I figure matching show/scene/shot (or variation) is a pretty common studio
pattern to match and would probably be best suited as one pattern with
capture groups. It might even be nice to capture named groups:
match =
re.search(r'ch(?P<ch>\d{2})\\seq(?P<seq>\d{3})\\s(?P<shot>\d{4})', path)
match.groupdict()
# {'ch': '01', 'seq': '001', 'shot': '0090'}
On Sat, Nov 9, 2013 at 1:12 PM, Chad Dombrova <[email protected]> wrote:
> not sure if someone answered this already, but here you go:
>
> >>> re.findall(r'(?:ch\d{2})|(?:seq\d{2})|(?:s\d{4})', r'P:\<various
> directories>\scene\ch01\seq001\s0090\anim\.......')
> ['ch01', 'seq00', 's0090']
>
> {2} means repeat the pattern 2 times
> ?: means do not capture inside these parentheses
>
>
>
> On Fri, Nov 8, 2013 at 5:35 AM, <[email protected]> wrote:
>
>> asd
>> On Tuesday, October 1, 2013 3:36:55 PM UTC+5:30, Panupat Chongstitwattana
>> wrote:
>> > Hi.
>> >
>> > I have this string
>> >
>> > path = r'P:\<various directories>\scene\ch01\seq001\s0090\anim\.......'
>> >
>> > I want to split out the ch01, seq001 and s0090 into 3 variables (or a
>> list). Is there a way to do this with regex in a single line? Maybe with
>> re.split(...)
>> >
>> > Currently I do it in 3 different steps
>> >
>> > find = re.findall(r'ch\d\d', path)
>> > if find: ch = find[0]
>> >
>> > find = re.findall(r'seq\d\d', path)
>> > if find: seq = find[0]
>> >
>> > etc.
>> >
>> > Thanks
>>
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