cool thanks Geordie,
yea i guess subtraction bit is easier, but i would think overall both
methods would take as long to write out with having to make pynodes to
begin with. But its a nice alternative
thanks,
Sam
On 22 March 2016 at 02:58, Geordie Martinez <geordiemarti...@gmail.com>
wrote:
> you can make it a LOT easier of you just stay in pymel and skip maya.cmds.
> here is an example of what you’re doing:
>
> import pymel.core as pm
> # make pynodes out of each locator or transform
> loc1=pm.PyNode('locator1')
> loc2=pm.PyNode('locator2')
> loc3=pm.PyNode('locator3')
> # get the World space position of each locator# each of these returns a Point
> pt1=loc1.getTranslation(space='world')
> pt2=loc2.getTranslation(space='world')
> pt3=loc3.getTranslation(space='world')
> # to get vectors subtract one point from another# returns a Vector
> vec1=pt2 - pt1
> vec2=pt3 - pt1
> # .cross() is a method on any vector
> cross = vec1.cross(vec2).normal() # add .normal() to normalize
>
>
>
> On Mon, Mar 21, 2016 at 8:10 AM, <s...@weacceptyou.com> wrote:
>
>> sorry i meant to write this the first time. this seems to work:
>>
>> ####
>> pt1=cmds.pointPosition('locator1')
>> pt2=cmds.pointPosition('locator2')
>> pt3=cmds.pointPosition('locator3')
>>
>> vec1=pm.dt.Vector(pt2[0]-pt1[0],pt2[1]-pt1[1],pt2[2]-pt1[2])
>> vec2=pm.dt.Vector(pt3[0]-pt1[0],pt3[1]-pt1[1],pt3[2]-pt1[2])
>>
>> perpenVec=vec1^vec2
>> ###
>>
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